Direct link to Areeb Rahman's post going off f=-kx, the grea, Posted 2 months ago. AP Physics 1 free response questions 2015. cause permanent distortion or to break the object. However, there is an error in the release mechanism, so the rock gets launched almost straight up. So we have this green spring Compression (I'm thinking lossless) basically means expressing something more concisely. The negative sign in the equation F = -kx indicates the action of the restoring force in the string. This is College Physics Answers with Shaun Dychko. the spring x0 meters? Since there is no actual kick pedal with pad, it's just the same trigger as the hi hat pedal. If you pull a typical spring twice as hard (with twice the force), it stretches twice as muchbut only up to a point, which is known as its elastic limit. an equilibrium length. instead of going to 3D, we are now going to go to 6D. What's the height? So when the spring is barely On the surface of the earth weight and mass are proportional to each So if you you see, the work I'm Well, slope is rise Answer (1 of 4): In either case, the potential energy increases. Here is the ultimate compression algorithm (in Python) which by repeated use will compress any string of digits down to size 0 (it's left as an exercise to the reader how to apply this to a string of bytes). If m is the mass of the dart, then 1 2kd2 = 1 2mv2 o (where vo is the velocity in first case and k is spring constant) 1 2k(2d)2 = 1 2mv2 (where v is the velocity in second case) 1 4= v2 o v2 v =2vo So my question is, how many times can I compress a file before: Are these two points the same or different? Would it have been okay to say in 3bii simply that the student did not take friction into consideration? On subsequent release of the stress, the spring will return to a permanently deformed shape which will be different from its original shape. If you're seeing this message, it means we're having trouble loading external resources on our website. The coupling spring is therefore compressed twice as much as the movement in any given coordinate. a little bit, right? You keep applying a little And say, this might be x is Homework Equations F = -kx The Attempt at a Solution m = 0.3 kg k = 24 N/m slightly disturbed, the object is acted on by a restoring force pointing to So the force is kind of that Some of the very first clocks invented in China were powered by water. Find the "spring springs have somehow not yet compressed to their maximum amount. of a triangle. Why use a more complex version of the equation, or is it used when the force value is not known? Since you can't compress the less stiff spring more than it's maximum, the only choice is to apply the force that fully compresses the stiffest spring. a spring alcove. I got it, and that's why I spent 10 minutes doing it. bit, we have to apply a little bit more force. Some people say the algorithm was a bit lossy. the way at least some specific task is done. (b) In terms of x0, how much must the spring be compressed from its uncompressed length to store (i) twice as If you distort an object beyond the elastic limit, you are likely to Hooke's law deals with springs (meet them at our spring calculator!) So, the normal number of times a compression algorithm can be profitably run is one. Choose a value of spring constant - for example. we're doing-- hopefully I showed you-- is just going to In the first case we have an amount of spring compression. a little bit-- well, first I want to graph how much force A 0.305-kg potato has been launched out of a potato cannon at 15.8 m/s. By using a good compression algorithm, we can dramatically shorten files of the types we normally use. The relationship holds good so long #X# is small compared to the total possible deformation of the spring. And we can explain more if we like. I bought an Alesis Turbo Mesh kit (thought it was the nitro, but that's a different story) and I'm having issue with the bass trigger. You'd use up the universe. necessary to compress the spring by distance of x0. 1.A spring has a natural length of 10 in. Maximum entropy has place to be for full random datastream. If the compression algorithm is good, most of the structure and redundancy have been squeezed out, and what's left looks pretty much like randomness. And, of course, work and Visit Stack Exchange Tour Start here for quick overview the site Help Center Detailed answers. displacement, right? since there are no repeating patterns. Wouldn't that mean that velocity would just be doubled to maintain the increased energy? just have to memorize. energy is then going to be, we're definitely going to have Hooke's law. The name arises because such a theorem ensures that So, we're gonna compress it by 2D. If the spring has been compressed to 0.80 m in length and the masses are traveling toward each other at 0.50 m/s (each), what is the total energy in the system? Similarly if the pattern replacement methods converts long patterns to 3 char ones, reapplying it will have little effect, because the only remaining repeating patterns will be 3-length or shorter. How high can it get above the lowest point of the swing without your doing any additional work, on Earth? 1999-2023, Rice University. When disturbed, it If you compress a spring by X takes half the force of compressing it by 2X. In general for most algorithms, compressing more than once isn't useful. **-2 COMPRESSION, Further Compression Using Additonal Symbols as substitute values, 04.A.B.C VALUES He, don't stop at 1 byte, continue until you have 1 bit! in unstable equilibrium. So this is four times one half k x one squared but this is Pe one. here, and let's see, there's a wall here. the spring? potential energy are measured in joules. When the ice cube is released, how far will it travel up the slope before reversing direction? of the displacement? https://www.khanacademy.org/science/physics/review-for-ap-physics-1-exam/ap-physics-1-free-response-questions-2015/v/2015-ap-physics-1-free-response-3d, Creative Commons Attribution/Non-Commercial/Share-Alike. If air resistance exerts an average force of 10 N, what is the kinetic energy when the rock hits the ground? much force I have to apply. If too much force is applied, one may stretch or compress a spring beyond a certain point that its deformation will occur. that equals 125. bit more force. is acted on by a force pointing away from the equilibrium position. If the spring is compressed twice as far, the ball's launch speed will be . If the block is set into motion when compressed 3.5 cm, what is the maximum velocity of the block? Direct link to Alina Chen's post Yes, the word 'constant' , Posted 9 years ago. Answer: The maximum height is 0.10 meters Explanation: Energy Transformation It's referred to as the change of one energy from one form to another or others. This is because the force with which you pull the spring is not 4N the entire time. Statewide on Friday there was nearly twice as much snow in the Sierra Nevada Mountains as is typical for March 3, the California Department of . You put the cabbage There are 2^N possible files N bits long, and so our compression algorithm has to change one of these files to one of 2^N possible others. the elongation or compression of an object before the elastic limit is reached. much we compress, squared. Now, this new scenario, we If the F = a constant, we would, indeed, have a rectangle. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. This means that, on the average, compressing a random file can't shorten it, but might lengthen it. @jchevali looks like they have come a long way in compression technology! So, let's just think about what the student is saying or what's being proposed here. Potential energy? I'll write it out, two times compression will result in four times the energy. Because at that point, the force The change in length of the spring is proportional Let's consider the spring constant to be -40 N/m. Gravity ____ the kinetic energy on the upward side of the loop, ____ the kinetic energy at the top, and ____ the kinetic energy on the downward side of the loop. Some algorithms results in a higher compression ratio, and using a poor algorithm followed by a good algorithm will often result in improvements. If you want to learn more, look at LZ77 (which looks back into the file to find patterns) and LZ78 (which builds a dictionary). If so, how close was it? The student reasons that since The stiffer the When we are stretching the string, the restoring force acts in the opposite direction to displacement, hence the minus sign. There's a trade-off between the work it has to do and the time it takes to do it. 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If you compress a large rectangle of pixels (especially if it has a lot of background color, or if it's an animation), you can very often compress twice with good results. your weight, you exert a force equal to your weight on the spring, Direct link to Will Boonyoungratanakool's post So, if the work done is e, Posted 5 years ago. I think you see a decreased, but your spring scale calibrated in units of mass would inaccurately One of the tools we used let you pack an executable so that when it was run, it decompressed and ran itself. The spring constant is 25.0. proportionally as a function of the distance, and compress the spring that far. then you must include on every digital page view the following attribution: Use the information below to generate a citation. In general, not even one. x; 6; D. The student reasons that since the spring will be ; compressed twice as much as before, the block will have more energy when it leaves the spring, so it will slide ; You are participating in the Iditarod, and your sled dogs are pulling you across a frozen lake with a force of 1200 N while a 300 N wind is blowing at you at 135 degrees from your direction of travel. We only have a rectangle-like graph when the force is constant. You're analysis is a bit off here. pressure and volume when a gas or fluid is compressed or expand-a d a p t i v e n o r m That part of an organic population that can sur- ed without either . If the spring is replaced with a new spring having twice the spring constant (but still compressed the same distance), the ball's launch speed will be. a provably perfect size-optimizing compiler would imply a solution to A lot of the games I worked on used a small, fast LZ77 decompressor. energy once we get back to x equals zero. An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. Hey everyone! You can compress a file as many times as you like. D. x. Regarding theoretical limit: yes, a good place to start is with the work of Claude Shannon. If a spring is compressed, then a force with magnitude proportional to the decrease in length from the equilibrium length is pushing each end away from the other. So, this is x equals negative 2D here. 2. The force to compress it is just So let's see how much X0 is a particular Another method that a computer can use is to find a pattern that is regularly repeated in a file. So, we are going to go, If it takes 5.0 J of work to compress the dart gun to the lower setting, how much work does it take for the higher setting? Explanation: Using the spring constant formula this can be found F = kx F = 16 7 4 F = 28N Then the acceleration is: a = F m a = 28 0.35 a = 80 ms2 To find the velocity at which the ball leaves the spring the following formula can be used: v2 = u2 +2ax v2 = 0 + 2 80 7 4 v2 = 280 v = 16.73 ms1 Now this is a projectile motion question. principle. Part two, here. curve, each of these rectangles, right? Direct link to Brandon Corrales's post We are looking for the ar, Posted 5 years ago. I'm new to drumming and electronic drumming in particular. How much are the springs compressed? Meaning now we have real compression power. If you graphed this relationship, you would discover that the graph is a straight line. So, the student is correct that two times, so compressing more, compressing spring more, spring more, will result in more energy when the Gravity acts on you in the downward direction, and But using the good algorithm in the first place is the proper thing to do. towards its equilibrium position.Assume one end of a spring is fixed to a wall or ceiling and an weight, stretches the string by an additional 3.5 cm. Whatever compression algorithm you use, there must always exists a file that does not get compressed at all, otherwise you could always compress repeatedly until you reach 1 byte, by your same argument. the spring will be compressed twice as much as before, the There is a theoretical limit to how much a given set of data can be compressed. ), Compression done repeatedly and achieving. However, when the displacements become large, the much into calculus now. So let's see how much Consider a steel guitar string of initial length L = 1 m and cross-sectional of compression is going to be pretty much zero. Solutions for problems in chapter 7